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n^2/5n-24=0
Domain of the equation: 5n!=0We multiply all the terms by the denominator
n!=0/5
n!=0
n∈R
n^2-24*5n=0
Wy multiply elements
n^2-120n=0
a = 1; b = -120; c = 0;
Δ = b2-4ac
Δ = -1202-4·1·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-120}{2*1}=\frac{0}{2} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+120}{2*1}=\frac{240}{2} =120 $
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